model 3 gain/loss % with C.P/S.P Practice Questions Answers Test with Solutions & More Shortcuts

Question : 6 [SSC CGL Tier-II 2013]

On selling 17 balls at 720, there is a loss equal to the cost price of 5 balls. The cost price (in ) of a ball is

a) 55

b) 50

c) 60

d) 45

Answer: (c)

Let C.P. of a ball = x

S.P. of 17 balls = Rs.720

17x - 720 = 5x

12x = 720 ⇒ x = Rs.60

Question : 7 [SSC CGL Tier-I 2016]

An article is sold at a certain price. If it is sold at half of the previous selling price, then there is a loss of 25$1/2$ % . The profit after selling the article at the previous selling price is:

a) 12$3/4$%

b) 49%

c) 24$1/2$%

d) 51%

Answer: (b)

Let the C.P. of article be Rs.100 and its S.P. be Rs.x.

According to the question.

When S.P. = Rs.$x/2$

Loss per cent = ${100 - x/2}/100 × 100$

$100 - x/2 = 51/2$

$x/2 = 100 - 51/2 = {200 - 51}/2$

x = Rs.149

Required profit percent = 49%

Question : 8 [SSC CGL Tier-I 2011]

A clock was sold for 144. If the percentage of profit was numerically equal to the cost price, the cost of the clock was

a) 90

b) 80

c) 100

d) 72

Answer: (b)

Let the cost price be x.

(100 + x)% of x = 144

(100 + x)x = 14400

$x^2 + 100x - 14400$ = 0

$x^2 + 180x - 80x - 14400$ = 0

x(x + 180) - 80 (x + 180) = 0

(x + 180) (x - 80) = 0

x = Rs.80 [x ≠180]

Question : 9 [SSC DEO 2009]

By selling 1 dozen ball pens, a shopkeeper earned the profit equal to the selling price of 4 ball pens. His profit per cent is

a) 33$1/3$%

b) 40%

c) 31$1/4$%

d) 50%

Answer: (d)

SP of 12 ball pens = CP of 12 ball pens + SP of 4 ball pens.

SP of 8 ball pens = CP of 12 ball pens

Gain per cent = $4/8 × 100 = 50%$

Using Rule 9,

Here, x = 12, y = 4

∴ Profit% = ${y × 100}/{x - y}$

= ${4 × 100}/{12 - 4}$ = 50%

Question : 10 [SSC MTS 2013]

The loss incurred on selling 21 articles equals the selling price of 3 articles. Then the loss per cent is

a) 12$1/2$%

b) 10%

c) 11$1/9$%

d) 9$1/11$%

Answer: (a)

S.P. of 3 articles

= C.P. of 21 articles - S.P. of 21 articles

S.P. of 24 articles = C.P. of 21 articles

Loss percent = ${24 - 21}/24 × 100 = 12{1}/2%$

Using Rule 9,

Here, x = 21, y = 3

∴ Loss% = ${y × 100}/{x + y}$

= ${3 × 100}/{21 + 3} = 100/8$

= $25/2 = 12{1}/2%$

IMPORTANT quantitative aptitude EXERCISES

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